# How do you solve  y=2x^2-4x-48 by factoring?

$y = 2 \left(x + 4\right) \left(x - 6\right)$
is the factored form of
$y = 2 {x}^{2} - 4 x - 48$

#### Explanation:

$y = 2 {x}^{2} - 4 x - 48$
Now,
Dividing the equation by 2
$\frac{1}{2} y = \frac{1}{2} \left(2 {x}^{2} - 4 x - 48\right)$
$\frac{1}{2} y = {x}^{2} - 2 x - 24$
${x}^{2} - 2 x - 24 = {x}^{2} + 4 x - 6 x - 24$
$= \left({x}^{2} + 4 x\right) - \left(6 x + 24\right)$

$\frac{1}{2} y = x \left(x + 4\right) - 6 \left(x + 4\right)$
$\frac{1}{2} y = \left(x + 4\right) \left(x - 6\right)$
$y = 2 \left(x + 4\right) \left(x - 6\right)$
is the factored form of
$y = 2 {x}^{2} - 4 x - 48$