How do you solve $(x-5)^2=4$ ?

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Answer 1 · 2017-06-15T12:13:39

Solution: $x=7 or x=3$

$(x-5)^2=4 or x-5 =sqrt4 or x-5 = +-2 or x=5+-2 :. x=7 or x=3$

Solution: $x=7 or x=3$ [Ans]

Answer 2 · 2017-06-15T12:15:44

$x=3or x=7$

If $(x-5)^2=4$
then
$color(white)("XXX")x-5=+-sqrt(4)=+-2$

${:("if " x-5=-2,color(white)("xxx"),"if "x=+2), ("then " x=3,,"then "x=7) :}$

How do you solve (x-5)^2=4 (x-5)^2=4?