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How do you solve $4 x^{2} - 49 = 0$ $4x^2-49=0$ by taking square roots?

1 Answer

Apr 16, 2018

$x = \pm \frac{7}{2}$ $x= +-7/2$

Explanation:

$4 x^{2} - 49 = 0$ $4x^2-49=0$

Add $49$ $49$ to both sides
$4 x^{2} = 49$ $4x^2=49$
Divide both sides by $4$ $4$
$x^{2} = \frac{49}{4}$ $x^2= 49/4$
Square root both sides
$x = \pm \sqrt{\frac{49}{4}}$ $x= +-sqrt(49/4)$
$x = \pm \frac{7}{2}$ $x= +-7/2$

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