How do you solve $(x-3)^2-18=0$ ?

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Answer 1 · 2017-06-06T19:05:07

$x = +7.243 or x = -1.243$

As the equation in given there is no $x$ term.

Find the square root of both sides:

$(x-3)^2 -18=0$

$(x-3)^2 = 18$

$x-3 =+-sqrt18$

$x = +sqrt18+3 = +7.243$
$x= -sqrt18+3=-1.243$

How do you solve (x-3)^2-18=0(x-3)^2-18=0?