How do you solve $x^{2} + 8 x = 0$ $x^2 + 8x = 0$ ?

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Answer 1 · 2016-10-04T07:04:40

$x = 0 or x = - 8$ $x=0 " or " x = -8$

Find the factors.

$x^{2} + 8 x = 0 \leftarrow$ $x^2 +8x=0" "larr$ there is a common factor

$x (x + 8) = 0$ $x(x+8)=0$

The product is 0, either factor could be 0.

$x = 0$ $x =0$

Or $x + 8 = 0, \to x = - 8$ $x+8 = 0, " "rarr x =-8$

How do you solve x^2 + 8x = 0x2+8x=0x^2 + 8x = 0?