How do you solve for x in $x^2-6x+4=0$ ?

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Answer 1 · 2015-02-07T15:09:23

I would find the roots for this equation using the qudratic formula

$x^2−6x+4=0$ Step 1: Use quadratic formula with a=1, b=-6, c=4.
x=
$−b±sqrt(b2−4ac)/ 2a$
$x= −(−6)±sqrt((−6)2−4(1)(4))/ 2(1)$
$x= 6±sqrt(20)/ 2$

$x=5.23606797749979,0.7639320225002102$
Answer:
$x=5.23606797749979,0.7639320225002102$

How do you solve for x in x^2-6x+4=0x^2-6x+4=0?