How do you solve ${(x - 2)}^{\frac{3}{2}} = 8$ $(x-2)^(3/2)=8$ ?

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Answer 1 · 2015-04-11T20:27:06

${(x - 2)}^{\frac{3}{2}} = 8$ $(x-2)^(3/2) = 8$

Take the cube root of both sides:
${(x - 2)}^{\frac{1}{2}} = 2$ $(x-2)^(1/2) = 2$

Square both sides
$(x - 2) = 4$ $(x-2) = 4$

Solve for $x$ $x$
$x = 6$ $x = 6$

How do you solve (x−2)32=8(x-2)^(3/2)=8?