How do you solve \sqrt{x+15}=\sqrt{3x-3}?

1 Answer
Jim G.
Mar 1, 2018

x=9

Explanation:

"To 'undo' the radicals square both sides"

(sqrt(x+15))^2=(sqrt(3x-3))^2

rArrx+15=3x-3

"subtract "(x+15)" from both sides"

rArr0=2x-18

rArr2x=18rArrx=9

color(blue)"As a check"

"substitute "x=9" into the equation and if both sides are"
"equal then it is the solution"

"left side "=sqrt24=2sqrt6

"right side "=sqrt24=2sqrt6

rArrx=9" is the solution"

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