# How do you solve x+12<=5 or 3x-21>=0?

Jun 25, 2018

$x \le - 7$ or $x \ge 7$

#### Explanation:

First you have to - the constant (the number that doesn't multiply by x)

Then divide by the coefficient

$3 x - 21 \ge 0$

constant = -21

$3 x - 21 - - 21 \ge - 21$

$3 x \ge - 21$

coefficient is 3

$\frac{3 x}{3} \ge \frac{- 21}{3}$

$x \ge - 7$

Jul 5, 2018

$x \le - 7$ or $x \ge 7$

#### Explanation:

Let's start with our first inequality and subtract $12$ from both sides to get

$x \le - 7$

For our second inequality, we can add $21$ to both sides to get

$3 x \ge 21$

Our last step would be to divide both sides by $3$. We get

$x \ge 7$

Therefore our solution set for both of these inequalities is

$x \le - 7$ or $x \ge 7$

Hope this helps!