How do you solve using the square root method #2x^2-5=93#?

1 Answer
EZ as pi
May 5, 2016

There is no #x# term, so we can just find the square root.
Remember that a number has a positive root and a negative root.

Explanation:

#2x^2 - 5 = 93#

#color(white)(xxx)##2x^2# = #93 +5#

#color(white)(xxx)##2x^2 = 98# #color(white)(xxxxxxxxx)# divide by 2.

#color(white)(xxx)##x^2 = 49#

#x = +-sqrt49#
#x = +-7#

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