How do you solve using the quadratic formula $6x^2 - 6x = x + 9$ ?

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Answer 1 · 2015-05-28T12:23:03

Rewrite $6x^2-6x = x+9$
into the standard $ax^2+bx+c=0$ form:

$6x^2-7x-9=0$

The quadratic formula for roots is
$x = (-b+-sqrt(b^2-4ac))/(2a)$

with the given example
$x= (7+-sqrt(49+216))/12$

$= (7+-sqrt(265))/12$

How do you solve using the quadratic formula 6x^2 - 6x = x + 96x^2 - 6x = x + 9?