How do you solve using the quadratic formula $4x-3x^2=1$ ?

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Answer 1 · 2015-05-09T20:58:49

The quadratic formula for roots
$x=(-b+-sqrt(b^2-4ac))/(2a)$
is applicable to equations in the form:
$ax^2+bx+c=0$

So first it will be necessary to rearrange $4x-3x^2=1$ as
$3x^2-4x+1=0$

Then
$x= (4+-sqrt(4^2-4(3)(1)))/(2(3))$

$= (4+-2)/6$

$x=1$ or $x=1/3$

How do you solve using the quadratic formula 4x-3x^2=14x-3x^2=1?