How do you solve the inequality #(x +4) + (x+6)> 3x - 1#?
1 Answer
Feb 4, 2016
Explanation:
1. Add like terms.
#(x+4)+(x+6)>3x-1#
#2x+10>3x-1#
2. Subtract 10 from both sides.
#2x+10# #color(red)(-10)>3x-1# #color(red)(-10)#
#2x>3x-11#
3. Subtract 3x from both sides.
#2x# #color(red)(-3x)>3x# #color(red)(-3x)-11#
#-x# #># #-11#
4. Divide both sides by -1.
#-xcolor(red)(-:-1)# #># #-11color(red)(-:-1)#
#x>11#
5. Flip the inequality sign.
Whenever you divide by a negative number, you must flip the inequality sign, even if you divide a negative number by another negative number.
#color(green)(x<11)#
