# How do you solve the inequality -x^2 - x + 6 <0?

May 12, 2018

$x < - 3 \text{ or } x > 2$

#### Explanation:

$\text{factor the quadratic}$

$- \left({x}^{2} + x - 6\right) < 0$

$\Rightarrow - \left(x + 3\right) \left(x - 2\right) < 0$

$\text{find the zeros by solving}$

$\left(x + 3\right) \left(x - 2\right) = 0$

$\Rightarrow x = - 3 \text{ or } x = 2$

$\text{since the coefficient of "x^2" term } < 0 \Rightarrow \bigcap$

$\Rightarrow x < - 3 \text{ or } x > 2$
graph{-x^2-x+6 [-10, 10, -5, 5]}