How do you solve the inequality $9 < 2 x + 6 < 21$ $9<2x+6<21$ ?

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Answer 1 · 2016-02-05T21:53:07

Start by subtracting 6 from each expression to get

$3 < 2 x < 15$ $3<2x<15$

Now divide each expression by 2 in order to isolate x.

$\frac{3}{2} < x < \frac{15}{2}$ $3/2< x<15/2$

$therefore x in (3/2,15/2)$ .

How do you solve the inequality 9<2x+6<219<2x+6<219<2x+6<21?