How do you solve the inequality #-5(k+ 4)>3(k-4)#?

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Answer 1 · 2016-01-07T11:45:12

k < - 1

first I'm going to reverse the inequality so that there is not a leading - sign.
When this is done the inequality symbol must be reversed.

# 3(k - 4 ) < - 5(k + 4 )

now multiply out the brackets.

#rArr 3k - 12 < - 5k - 20 #

now collect like terms.

3k + 5k < - 20 + 12

# rArr 8k <-8 #

now divide both sides by 8.

# rArr k < - 1 #