How do you solve the inequality $4 (7 - 3 x) \leq - 20$ $4(7-3x)<= -20$ ?

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Answer 1 · 2018-05-20T18:27:45

$x \geq 4$ $x>=4$

$4 (7 - 3 x) \leq - 20$ $4(7-3x)<= -20$

distributive property:

$28 - 12 x \leq - 20$ $28-12x<= -20$

$- 12 x \leq - 48$ $-12x<= -48$

$x \geq 4$ $x>=4$

remember you need to flip the inequality when you divide by a negative number.

How do you solve the inequality 4(7-3x)<= -204(7−3x)≤−204(7-3x)<= -20?