How do you solve the inequality #3-4(x-2) >=-5x+6#?

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Answer 1 · 2018-07-21T21:39:01

#x >= -5#

#3-4(x-2) >= -5x + 6#

Simplify the left hand side:
#3 - 4x + 8 >= -5x + 6#

#11 - 4x >= -5x + 6#

Add #color(blue)(5x)# to both sides:
#11 - 4x quadcolor(blue)(+quad5x) >= -5x + 6 quadcolor(blue)(+quad5x)#

#11 + x >= 6#

Subtract #color(blue)11# from both sides:
#11 + x quadcolor(blue)(-quad11) > 6 quadcolor(blue)(-quad11)#

#x >= -5#

Hope this helps!