How do you solve the inequality #-1/3<= (4x-1)/ 3< 1/2#?

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Answer 1 · 2017-02-15T12:34:26

#-1/3<= (4x-1)/ 3< 1/2#

#=>-1/3xx3<= (4x-1)/ 3xx3 < 1/2xx3#

#=>-1<= (4x-1)< 3/2#

#=>-1+1<= (4x-1+1)< 3/2+1#

#=>-0<= 4x< 5/2#

#=>-0/4<= (4x)/4< 5/2xx1/4#

#=>-0<= x< 5/8#