How do you solve the equation $x^{2} - 324 = 0$ $x^2-324=0$ ?

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Answer 1 · 2017-10-01T03:46:49

Given: $x^{2} - 324 = 0$ $x^2-324=0$

Add 324 to both sides:

$x^{2} = 324$ $x^2=324$

Use the square root on both sides:

$x = \pm 18$ $x=+-18$

This means that the solutions are $x = 18 and x = - 18$ $x = 18 and x = -18$

Answer 2 · 2017-10-01T03:54:22

$x = 18$ $x=18$

$x^{2} - 324 = 0$ $x^2-324=0$
$x^{2} = 324 = 18 \cdot 18 = 18^{2}$ $x^2=324=18*18=18^2$
$:.x=18$

Answer 3 · 2017-10-01T09:18:41

$x = 18 or x=-18$

This can be solved by factorising the quadratic using the difference of two squares.

$x^2-324 =0$

$(x+18)(x-18)=0$

Set each factor equal to $0$

$x+18=0 " "rarr x = -18$

$x-18=0" "rarr x =18$

How do you solve the equation x^2-324=0x2−324=0x^2-324=0?