How do you solve the equation $-4(x^2-8)=16$ ?

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Answer 1 · 2017-05-21T23:36:22

$x = +2 or x=-2$

There is no $x$ =term, so we can solve this by finding the square roots.

$-4(x^2-8)=16" "larr div -4$

$x^2 -8= -4" "larr$ add 8 to both sides

$x^2 = -4+8$

$x^2 = 4$

$x = +-sqrt4$

$x =+-2$

How do you solve the equation -4(x^2-8)=16-4(x^2-8)=16?