How do you solve the equation $3 cos θ - 1 = 4$ $3costheta-1=4$ for $0 \leq θ < 2 π$ $0<=theta<2pi$ ?

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Answer 1 · 2016-12-23T13:30:35

No solutions are possible for this equation.

The maximum value of $cos (θ)$ $cos(theta)$ for any value of $θ$ $theta$ is $1$ $1$

Therefore the maximum value of $3 cos (θ)$ $3cos(theta)$ is $3$ $3$
and
the maximum value of $3 cos (θ) - 1$ $3cos(theta)-1$ is $2$ $2$

Therefore $3 cos (θ) - 1$ $3cos(theta)-1$ can not be equal to $4$ $4$ for any value of $θ$ $theta$

How do you solve the equation 3costheta-1=43cosθ−1=43costheta-1=4 for 0<=theta<2pi0≤θ<2π0<=theta<2pi?