# How do you solve for x in #3sin2x=cos2x# for the interval #0 ≤ x < 2π#

##### 1 Answer

Feb 13, 2015

You can use the fact that

In your expression.:

(Graph from: http://www.intmath.com/trigonometric-graphs/4-graphs-tangent-cotangent-secant-cosecant.php)

and so to have

Hope it helps