How do you solve tanx(tanx-1)=0?

1 Answer
Alan P.
Aug 4, 2016

Assuming a domain of [0,2pi]
color(white)("XXX")color(green)(x in {0,pi/4,pi,(5pi)/4}

Explanation:

Given (at least this is what I think the expression meant):
color(white)("XXX")color(red)(""(tan(x)))*color(blue)(""(tan(x)-1))=0

Either
color(white)("XXX")color(red)(tan(x)=0)color(white)("XX")orcolor(white)("XX")color(blue)(tan(x)-1=0)

rArrcolor(white)("X")color(red)(x= 0" or " pi)color(white)("XXXXXX")color(blue)(tan(x)=1)

color(white)("XXXXXXXXXXXXXXXXX")color(blue)(rArrx=pi/4" or " (5pi)/4)

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