How do you solve $\sqrt{x + 8} = 6$ $sqrt(x + 8) =6$ ?

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Answer 1 · 2016-06-06T12:51:59

Square both sides then solve for x.
$x = 28$ $x = 28$

Start by squaring both sides to get rid of the square root.

${(\sqrt{x + 8})}^{2} = 6^{2} \Rightarrow x + 8 = 36$ $(sqrt(x + 8))^2 = 6^2 rArr " " x + 8 = 36$

Now solve as usual

$x = 36 - 8$ $x = 36 - 8$

$x = 28$ $x = 28$

How do you solve sqrt(x + 8) =6√x+8=6sqrt(x + 8) =6?