How do you solve #sqrt(n-5)=2sqrt3# and check your solution?

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Answer 1 · 2017-11-06T05:38:16

#n=17#

If you square both sides you will get rid of the square roots and from there it is plain sailing.

#sqrt(n-5)^2 = (2sqrt3)^2#

#n-5 = 4xx3#

#n-5=12#

#n =12+5=17#

To check the solution, substitute the value for #n# into the original equation.

Is #sqrt(n-5) = 2sqrt3#?

#sqrt(17-5)#

#=sqrt12#

#=sqrt(4xx3)#

#=2sqrt3" "# this checks out and the solution is correct.