How do you solve $sqrt(4x +16) = x +1$ ?

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Answer 1 · 2016-08-04T19:59:36

$x = 5 or x = -3$

First square both sides:

$(sqrt(4x +16))^2 = (x +1)^2$

$4x + 16 = x^2 +2x +1$

$x^2 +2x +1 -4x-16 = 0$

$x^2 -2x -15 = 0" find factors"$

$(x-5)(x+3) = 0$

$x = 5 or x = -3$

How do you solve sqrt(4x +16) = x +1sqrt(4x +16) = x +1?