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How do you solve $sqrt(-2x) + 64 = 6$ ?

1 Answer

Jul 31, 2015

There are no solutions to this equation

Explanation:

By convention
$color(white)("XXXX")$ $sqrt("anything") >= 0$

Therefore for any value of $x$
$color(white)("XXXX")$ $sqrt(-2x)+64$
$color(white)("XXXX")$ $color(white)("XXXX")$ $color(white)("XXXX")$ $>= 64$
$color(white)("XXXX")$ $color(white)("XXXX")$ $color(white)("XXXX")$ $!= 6$

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