How do you solve #(q - 12) 3 <5q + 2#?

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Answer 1 · 2016-07-12T18:52:09

#q> -19#

Multiply out the bracket on the left hand side:

#3*q - 3*12 < 5q +2#

#3q - 36 < 5q + 2#

Subtract #3q# from both sides of the inequality:

#-36 < 2q + 2#

Subtract 2 from both sides of the inequality:

#-38 < 2q#

Divide both sides by 2

#-19 < q#

So our solution is that #q> -19#