How do you solve $n^2+4=40$ ?

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Answer 1 · 2016-08-30T17:39:19

$n = +6 or n = -6$

Although this is a quadratic equation, it is a special case because it does not have a term in $x$ .

There are 2 methods:

$n^2 = 36$
$n = +-sqrt36$

$n = +6 or n = -6$

Or we can do the usual method of making it equal to 0 and finding factors:

$n^2 -36 = 0$

$(n+6)(n-6)= 0$

$n = -6 or n=+6$

How do you solve n^2+4=40n^2+4=40?