How do you solve #n^2+4=40#?

Question

2992 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-30T17:39:19

#n = +6 or n = -6#

Although this is a quadratic equation, it is a special case because it does not have a term in #x#.

There are 2 methods:

#n^2 = 36#
#n = +-sqrt36#

#n = +6 or n = -6#

Or we can do the usual method of making it equal to 0 and finding factors:

#n^2 -36 = 0#

#(n+6)(n-6)= 0#

#n = -6 or n=+6#