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How do you solve #ln3x=5#?

1 Answer

Shwetank Mauria

Oct 12, 2016

#x=e^5/3=49.471#

Explanation:

In #ln3x=5#, #ln# refers to Napier logarithm i.e. to base #e#

Hence, using definition of logarithm we have

#3x=e^5#

or #x=e^5/3=148.413/3=49.471#

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