How do you solve #ln2x=4#?

1 Answer
MathFact-orials.blogspot.com
Oct 16, 2016

#x=(e^4)/2~=27.3#

Explanation:

Start with the original:

#ln(2x)=4#

We can take both sides and put them as exponents of #e#. On the left side, this is taking one function (#ln#) and applying the inverse to it (#e#), so the result is that they cancel out and we end up with the term inside the #ln#:

#2x=e^4#

#x=(e^4)/2~=27.3#

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