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How do you solve #ln x - ln (1/x) = 2#?

1 Answer

Shwetank Mauria

Apr 27, 2018

#x=e#

Explanation:

As #lnx-ln(1/x)=2#

we have #ln(x/(1/x))=2#

or #lnx^2=2#

or #2lnx=2#

or #lnx=1#

and #x=e#

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