How do you solve #Ln(x)-2=0#?

1 Answer
sente
Jun 19, 2016

#x = e^2#

Explanation:

A logarithm #log_a(x)# is the value fulfilling the equation #a^(log_a(x))=x#.

#ln# represents the natural logarithm, that is, the logarithm with base #e#. To solve, then, we can isolate #ln(x)# and then apply the exponential function. As #ln(x)# is the same as #log_e(x)#, then #e^ln(x) = x#.

#ln(x) - 2 = 0#

#=>ln(x) = 2#

#=>e^(ln(x))= e^2#

#=> x = e^2#

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