How do you solve #Ln(x+1)-ln(x-2)=lnx^2#?

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How do you solve #Ln(x+1)-ln(x-2)=lnx^2#?

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Answer 1 · 2016-07-17T05:24:46

#x approx 2.54682#

Explanation:

#impliesln((x+1)/(x-2))=ln(x^2)#
#implies (x+1)/(x-2)=x^2#
#implies x+1=x^2(x-2)#
#implies x+1=x^3-2x^2#
#implies x^3-2x^2-x-1=0#
solve this equation with computer aid
#x approx 2.54682#

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How do you solve #Ln(x+1)-ln(x-2)=lnx^2#?

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