How do you solve ln(-m)=ln(m+10)?

Dec 21, 2016

$m = - 5$

Explanation:

Given:

$\ln \left(- m\right) = \ln \left(m + 10\right)$

Take exponents of both sides to find:

$- m = {e}^{\ln \left(- m\right)} = {e}^{\ln \left(m + 10\right)} = m + 10$

Add $m - 10$ to both ends to get:

$- 10 = 2 m$

Divide both sides by $2$ and transpose to get:

$m = - 5$