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How do you solve #Ln (Ln(Ln x)) = 0#?

1 Answer

Nov 29, 2016

As #y=e^x# is a single valued function defined everywhere on the real axis #a=b <=> e^a = e^b# for every real #a,b#.

Explanation:

#ln(ln(lnx))=0 <=> e^(ln(ln(lnx))) = e^0#

or:

#ln(lnx)) = 1#

and similarly:

#ln(x) = e#

#x= e^e#

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