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How do you solve #ln e^ln x - ln(x-2) = ln 8#?

1 Answer

Jun 18, 2016

#x=16/7#

Explanation:

#ln e^ln x - ln(x-2) = ln 8#

#=>ln x - ln(x-2) = ln 8#

#=>ln (x/(x-2) )= ln 8#

#=> (x/(x-2) )= 8#

#=>8x-16=x#

#=>7x=16=>x=16/7#

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