How do you solve #Ln(5x-4)=ln2+ln(x+1)#?

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How do you solve #Ln(5x-4)=ln2+ln(x+1)#?

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Answer 1 · 2016-05-13T16:19:30

#x=2#

Explanation:

Taking #ln(5x-4) = ln(2)+ln(x+1)# or equivalently #ln(5x-4)-ln(2*(x+1))=0# or #ln[(5x-4)/(2(x+1))]= ln(1)# then results in
#(5x-4)/(2(x+1))=1# or #5x-4=2(x+1)# and finally #x = 2#

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How do you solve #Ln(5x-4)=ln2+ln(x+1)#?

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