How do you solve #ln(-2x)=ln(3x+10)#?
1 Answer
Sep 4, 2016
Explanation:
Using the
#color(blue)"law of logarithms"#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(lnx=lnyrArrx=y)color(white)(a/a)|)))#
#rArr-2x=3x+10rArr-5x=10rArrx=-2#
