How do you solve #ln(1-8n)-10=-7#?

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Answer 1 · 2018-06-13T14:08:01

#n=(1-e^3)/8~~-2.386#

#ln(1-8n)-10=-7#

#ln(1-8n)=3#

#1-8n=e^3#

#8n=1-e^3#

#n=(1-e^3)/8~~-2.386#

Answer 2 · 2018-06-13T14:09:37

#n = \frac{1-e^3}{8}#

Add #10# to both sides:

#ln(1-8n) = 3#

Consider both sides as exponents of #e#:

#e^{ln(1-8n)} = e^3#

#\therefore 1-8n = e^3#

Subtract #1# from both sides

#-8n = e^3-1#

Divide both sides by #-8#:

#n = \frac{1-e^3}{8}#