How do you solve #k/3-14<-5# and graph the solution on a number line?

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Answer 1 · 2018-07-21T21:08:16

#k < 27#

To solve this, first add #color(blue)14# to both sides of the inequality:
#k/3 - 14 quadcolor(blue)(+quad14) < -5 quadcolor(blue)(+quad14)#

#k/3 < 9#

Multiply both sides by #color(blue)3#:
#k/3 color(blue)(*3) < 9 color(blue)(*3)#

#k < 27#

This can be said as "#k# is less than #27#."

Here's a graph of it on a number line:
enter image source here
(mathwarehouse.com)

The open circle on #27# means that #27# is one of the solutions (and anything less than it).

Hope this helps!