How do you solve for y in #Ln (y-1) = 3 ln x +2#?
The graph is that part in Q1, above (0, 1), sans (0, 1)..
To keep logarithms as real numbers,
The graph is the part of this curve in #Q_1
and is above (0, 1), sans (0, 1).
Of course, the whole curve ( not the given part ) meets the x-axis y
= 0, at