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How do you solve for x in #sin(x) = sin(2x)# where x is between [0,360]?

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Feb 15, 2015

#x epsilon {0^o, 60^o, 180^o, 330^o}#

#sin(x) = sin(2x)#
By double angle formula:
#sin(x) = 2 * sin(x) * cos(x)#
#sin(x) = 0# or # 1 = 2 * cos(x)#

If #sin(x) = 0#
then #x = 0^O or 180^o#

If #1 = 2 * cos(x)#
then #cos(x) = 1/2#
#rarr# #x = 60^o or 330^O#

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