How do you solve for x: #-4/5(x-3)≤-12#?

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Answer 1 · 2018-06-17T22:41:50

#x = 18#

#-4/3(x-3) <= -12#

First, divide both sides by #color(blue)(-4)#:
#(-4/5(x-3))/color(blue)(-4) <= (-12)/color(blue)(-4)#

#1/5(x-3) <= 3#

Now multiply both sides by #color(blue)5#:
#1/5(x-3) color(blue)(*5) <= 3 color(blue)(*5)#

#x-3 <= 15#

Add #color(blue)3# to both sides:
#x - 3 quadcolor(blue)(+quad3) <= 15 quadcolor(blue)(+quad3)#

Therefore,
#x <= 18#

Hope this helps!