# How do you solve for the power of #x#? For example, #2^x = 423#. How do you get #x#?

##### 1 Answer

Oct 2, 2014

**Take the natural log of both sides**

**Use one of properties of logs to move the exponent down as a factor**

**Use Algebra to solve for #x# by dividing by #ln(x)#**

**Use a calculator to resolve the division**