How do you solve for $h$ ? $-4h+3+7h≥9h-21$

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Answer 1 · 2018-04-09T14:04:30

We will first rearrange to put all $h$ s on one side:
$3le9h-7h+4h-21$
$3le6h-21$

Now we add $21$ to both sides:
$3+21le6h-21+21$
$24le6h$

$Finally, we divide both sides by$ 6 $:$ 24/6le(6h)/64leh#

How do you solve for hh? -4h+3+7h≥9h-21-4h+3+7h≥9h-21