How do you solve #e^(k+7)=26#?

1 Answer
Shell
Sep 6, 2016

Take the natural log of both sides.

Explanation:

Take the natural log of both sides.
#ln e^(k+7) = ln 26#

Using the property of logs that allows exponents to become coefficients...
#(k+7)lne = ln26#

The natural log of e is 1, so..
#k+7 =ln26#

Subtract 7 from both sides.
#k = ln26 -7#

Using a calculator,
#k=-3.742#

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