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How do you solve #e^(-5n-1)+3.9=75#?

1 Answer

Aug 27, 2016

#e^(-5n - 1) = 75 - 3.9#

#e^(-5n - 1) = 71.1#

#-5n - 1 = ln71.1#

#-5n = ln71.1 + 1#

#n = -1.05#

Hopefully this helps!

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