How do you solve #e^(-4x)+8=35#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Oct 1, 2016 #x=-0.824# Explanation: #e^(-4x)+8=35# #hArre^(-4x)=35-8=27# Hence, #-4x=ln27=3.2958369# from scientific calculator #x=-3.2958369/4=-0.824# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 2020 views around the world You can reuse this answer Creative Commons License